1/(x+1)-1/(x-4)=0

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Solution for 1/(x+1)-1/(x-4)=0 equation: 


D( x )

x+1 = 0

x-4 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:-1) U (-1:4) U (4:+oo)

1/(x+1)-(1/(x-4)) = 0

1/(x+1)-(x-4)^-1 = 0

1/(x+1)-1/(x-4) = 0

(1*(x-4))/((x+1)*(x-4))+(-1*(x+1))/((x+1)*(x-4)) = 0

1*(x-4)-1*(x+1) = 0

-5 = 0

-5/((x+1)*(x-4)) = 0

-5/((x+1)*(x-4)) = 0 // * (x+1)*(x-4)

-5 = 0

x belongs to the empty set

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