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20-6+4k=2-2k^2
We move all terms to the left:
20-6+4k-(2-2k^2)=0
We add all the numbers together, and all the variables
-(2-2k^2)+4k+14=0
We get rid of parentheses
2k^2+4k-2+14=0
We add all the numbers together, and all the variables
2k^2+4k+12=0
a = 2; b = 4; c = +12;
Δ = b2-4ac
Δ = 42-4·2·12
Δ = -80
Delta is less than zero, so there is no solution for the equation
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