20=35-5(2x+3)

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Solution for 20=35-5(2x+3) equation: 



20=35-5(2x+3)

We move all terms to the left:

20-(35-5(2x+3))=0



We calculate terms in parentheses: -(35-5(2x+3)), so:

35-5(2x+3)

determiningTheFunctionDomain
-5(2x+3)+35

We multiply parentheses

-10x-15+35

We add all the numbers together, and all the variables

-10x+20

Back to the equation:

-(-10x+20)



We get rid of parentheses

10x-20+20=0

We add all the numbers together, and all the variables

10x=0

x=0/10

x=0

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