20+5-11x=10(1/2-6x)

Solution for 20+5-11x=10(1/2-6x) equation:

20+5-11x=10(1/2-6x)

We move all terms to the left:

20+5-11x-(10(1/2-6x))=0


Domain of the equation: 2-6x))!=0

We move all terms containing x to the left, all other terms to the right

-6x))!=-2

x!=-2/1

x!=-2

x∈R


We add all the numbers together, and all the variables

-11x-(10(-6x+1/2))+20+5=0

We add all the numbers together, and all the variables

-11x-(10(-6x+1/2))+25=0

We multiply all the terms by the denominator


-11x*2))-(10(-6x+1+25*2))=0

We add all the numbers together, and all the variables

-11x*2))-(10(-6x+51))=0

We add all the numbers together, and all the variables

-6x-11x*2))-(10(=0

Wy multiply elements

-22x^2-6x=0

a = -22; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-22)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-22}=\frac{0}{-44}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-22}=\frac{12}{-44}
=-3/11
$