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(7x-5)=(2x+15)
We move all terms to the left:
(7x-5)-((2x+15))=0
We get rid of parentheses
7x-((2x+15))-5=0
We calculate terms in parentheses: -((2x+15)), so:We get rid of parentheses
(2x+15)
We get rid of parentheses
2x+15
Back to the equation:
-(2x+15)
7x-2x-15-5=0
We add all the numbers together, and all the variables
5x-20=0
We move all terms containing x to the left, all other terms to the right
5x=20
x=20/5
x=4
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