20+3y-4=14y-12-4y

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Solution for 20+3y-4=14y-12-4y equation: 



20+3y-4=14y-12-4y

We move all terms to the left:

20+3y-4-(14y-12-4y)=0

We add all the numbers together, and all the variables

3y-(10y-12)+20-4=0

We add all the numbers together, and all the variables

3y-(10y-12)+16=0

We get rid of parentheses

3y-10y+12+16=0

We add all the numbers together, and all the variables

-7y+28=0

We move all terms containing y to the left, all other terms to the right

-7y=-28

y=-28/-7

y=+4

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