-4(5-v)/11=10(v+9)/1

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Solution for -4(5-v)/11=10(v+9)/1 equation: 



-4(5-v)/11=10(v+9)/1

We move all terms to the left:

-4(5-v)/11-(10(v+9)/1)=0

We add all the numbers together, and all the variables

-4(-1v+5)/11-(10(v+9)/1)=0

We calculate fractions


4v/()+(-(10(v+9)*11)/()=0



We calculate terms in parentheses: +(-(10(v+9)*11)/(), so:

-(10(v+9)*11)/(

We multiply all the terms by the denominator


-(10(v+9)*11)



We calculate terms in parentheses: -(10(v+9)*11), so:

10(v+9)*11

We multiply parentheses

110v+990

Back to the equation:

-(110v+990)



We get rid of parentheses

-110v-990

Back to the equation:

+(-110v-990)



We get rid of parentheses

4v/()-110v-990=0

We multiply all the terms by the denominator


4v-110v*()-990*()=0

We add all the numbers together, and all the variables

4v-110v*()=0

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