20(x-2)=17(x+1)-18

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Solution for 20(x-2)=17(x+1)-18 equation: 



20(x-2)=17(x+1)-18

We move all terms to the left:

20(x-2)-(17(x+1)-18)=0

We multiply parentheses

20x-(17(x+1)-18)-40=0



We calculate terms in parentheses: -(17(x+1)-18), so:

17(x+1)-18

We multiply parentheses

17x+17-18

We add all the numbers together, and all the variables

17x-1

Back to the equation:

-(17x-1)



We get rid of parentheses

20x-17x+1-40=0

We add all the numbers together, and all the variables

3x-39=0

We move all terms containing x to the left, all other terms to the right

3x=39

x=39/3

x=13

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