20(5-x)=12(3x+4)

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Solution for 20(5-x)=12(3x+4) equation:



20(5-x)=12(3x+4)
We move all terms to the left:
20(5-x)-(12(3x+4))=0
We add all the numbers together, and all the variables
20(-1x+5)-(12(3x+4))=0
We multiply parentheses
-20x-(12(3x+4))+100=0
We calculate terms in parentheses: -(12(3x+4)), so:
12(3x+4)
We multiply parentheses
36x+48
Back to the equation:
-(36x+48)
We get rid of parentheses
-20x-36x-48+100=0
We add all the numbers together, and all the variables
-56x+52=0
We move all terms containing x to the left, all other terms to the right
-56x=-52
x=-52/-56
x=13/14

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