(0.06-x)(0.2-x)=0

Solution for (0.06-x)(0.2-x)=0 equation:

(0.06-x)(0.2-x)=0

We add all the numbers together, and all the variables

(-1x+0.06)(-1x+0.2)=0

We multiply parentheses ..

(+x^2-0.2x-0.06x+0.012)=0

We get rid of parentheses

x^2-0.2x-0.06x+0.012=0

We add all the numbers together, and all the variables

x^2-0.26x+0.012=0

a = 1; b = -0.26; c = +0.012;
Δ = b2-4ac
Δ = -0.262-4·1·0.012
Δ = 0.0196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.26)-\sqrt{0.0196}}{2*1}=\frac{0.26-\sqrt{0.0196}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.26)+\sqrt{0.0196}}{2*1}=\frac{0.26+\sqrt{0.0196}}{2}
$