(0.0125+x)(0.5+x)=0

Solution for (0.0125+x)(0.5+x)=0 equation:

(0.0125+x)(0.5+x)=0

We add all the numbers together, and all the variables

(x+0.0125)(x+0.5)=0

We multiply parentheses ..

(+x^2+0.5x+0.0125x+0.00625)=0

We get rid of parentheses

x^2+0.5x+0.0125x+0.00625=0

We add all the numbers together, and all the variables

x^2+0.5125x+0.00625=0

a = 1; b = 0.5125; c = +0.00625;
Δ = b2-4ac
Δ = 0.51252-4·1·0.00625
Δ = 0.23765625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5125)-\sqrt{0.23765625}}{2*1}=\frac{-0.5125-\sqrt{0.23765625}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5125)+\sqrt{0.23765625}}{2*1}=\frac{-0.5125+\sqrt{0.23765625}}{2}
$