20(-10x+15)=29(x-3)

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Solution for 20(-10x+15)=29(x-3) equation: 



20(-10x+15)=29(x-3)

We move all terms to the left:

20(-10x+15)-(29(x-3))=0

We multiply parentheses

-200x-(29(x-3))+300=0



We calculate terms in parentheses: -(29(x-3)), so:

29(x-3)

We multiply parentheses

29x-87

Back to the equation:

-(29x-87)



We get rid of parentheses

-200x-29x+87+300=0

We add all the numbers together, and all the variables

-229x+387=0

We move all terms containing x to the left, all other terms to the right

-229x=-387

x=-387/-229

x=1+158/229

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