40-(3c+4)=+2(c+6)+c

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Solution for 40-(3c+4)=+2(c+6)+c equation: 



40-(3c+4)=+2(c+6)+c

We move all terms to the left:

40-(3c+4)-(+2(c+6)+c)=0

We get rid of parentheses

-3c-(+2(c+6)+c)-4+40=0



We calculate terms in parentheses: -(+2(c+6)+c), so:

+2(c+6)+c

determiningTheFunctionDomain
2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)



We add all the numbers together, and all the variables

-3c-(3c+12)+36=0

We get rid of parentheses

-3c-3c-12+36=0

We add all the numbers together, and all the variables

-6c+24=0

We move all terms containing c to the left, all other terms to the right

-6c=-24

c=-24/-6

c=+4

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