20(-10+2x)=400

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Solution for 20(-10+2x)=400 equation: 



20(-10+2x)=400

We move all terms to the left:

20(-10+2x)-(400)=0

We add all the numbers together, and all the variables

20(2x-10)-400=0

We multiply parentheses

40x-200-400=0

We add all the numbers together, and all the variables

40x-600=0

We move all terms containing x to the left, all other terms to the right

40x=600

x=600/40

x=15

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