8(x+3)=4(x-2)

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Solution for 8(x+3)=4(x-2) equation: 



8(x+3)=4(x-2)

We move all terms to the left:

8(x+3)-(4(x-2))=0

We multiply parentheses

8x-(4(x-2))+24=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

8x-4x+8+24=0

We add all the numbers together, and all the variables

4x+32=0

We move all terms containing x to the left, all other terms to the right

4x=-32

x=-32/4

x=-8

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