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2/x=x/5x-12
We move all terms to the left:
2/x-(x/5x-12)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x-12)!=0We get rid of parentheses
x∈R
2/x-x/5x+12=0
We calculate fractions
(-1x^2)/5x^2+10x/5x^2+12=0
We multiply all the terms by the denominator
(-1x^2)+10x+12*5x^2=0
Wy multiply elements
(-1x^2)+60x^2+10x=0
We get rid of parentheses
-1x^2+60x^2+10x=0
We add all the numbers together, and all the variables
59x^2+10x=0
a = 59; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·59·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*59}=\frac{-20}{118} =-10/59 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*59}=\frac{0}{118} =0 $
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