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6x+1/2x=240
We move all terms to the left:
6x+1/2x-(240)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
6x*2x-240*2x+1=0
Wy multiply elements
12x^2-480x+1=0
a = 12; b = -480; c = +1;
Δ = b2-4ac
Δ = -4802-4·12·1
Δ = 230352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{230352}=\sqrt{16*14397}=\sqrt{16}*\sqrt{14397}=4\sqrt{14397}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-480)-4\sqrt{14397}}{2*12}=\frac{480-4\sqrt{14397}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-480)+4\sqrt{14397}}{2*12}=\frac{480+4\sqrt{14397}}{24} $
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