2/x-4-8/4x-16=10

Solution for 2/x-4-8/4x-16=10 equation:

2/x-4-8/4x-16=10

We move all terms to the left:

2/x-4-8/4x-16-(10)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

2/x-8/4x-30=0

We calculate fractions


8x/4x^2+(-8x)/4x^2-30=0

We multiply all the terms by the denominator


8x+(-8x)-30*4x^2=0

Wy multiply elements

-120x^2+8x+(-8x)=0

We get rid of parentheses

-120x^2+8x-8x=0

We add all the numbers together, and all the variables

-120x^2=0

a = -120; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-120)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-240}=0$