8(r-3)=3(r+4)-7r

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Solution for 8(r-3)=3(r+4)-7r equation: 



8(r-3)=3(r+4)-7r

We move all terms to the left:

8(r-3)-(3(r+4)-7r)=0

We multiply parentheses

8r-(3(r+4)-7r)-24=0



We calculate terms in parentheses: -(3(r+4)-7r), so:

3(r+4)-7r

We add all the numbers together, and all the variables

-7r+3(r+4)

We multiply parentheses

-7r+3r+12

We add all the numbers together, and all the variables

-4r+12

Back to the equation:

-(-4r+12)



We get rid of parentheses

8r+4r-12-24=0

We add all the numbers together, and all the variables

12r-36=0

We move all terms containing r to the left, all other terms to the right

12r=36

r=36/12

r=3

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