2/x+4+5/x-4=40/(x+4)(x-4)

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Solution for 2/x+4+5/x-4=40/(x+4)(x-4) equation: 



2/x+4+5/x-4=40/(x+4)(x-4)

We move all terms to the left:

2/x+4+5/x-4-(40/(x+4)(x-4))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+4)(x-4))!=0

x∈R



We add all the numbers together, and all the variables

2/x+5/x-(40/(x+4)(x-4))=0

We use the square of the difference formula

x^2+2/x+5/x+16=0

We multiply all the terms by the denominator


x^2*x+16*x+2+5=0

We add all the numbers together, and all the variables

x^2*x+16x+7=0

Wy multiply elements

x^3+16x+7=0

We do not support expression: x^3

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