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2/x+3+1/12=3/2x-1
We move all terms to the left:
2/x+3+1/12-(3/2x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-1)!=0We get rid of parentheses
x∈R
2/x-3/2x+1+3+1/12=0
We calculate fractions
4x^2/24x^2+48x/24x^2+(-36x)/24x^2+1+3=0
We add all the numbers together, and all the variables
4x^2/24x^2+48x/24x^2+(-36x)/24x^2+4=0
We multiply all the terms by the denominator
4x^2+48x+(-36x)+4*24x^2=0
Wy multiply elements
4x^2+96x^2+48x+(-36x)=0
We get rid of parentheses
4x^2+96x^2+48x-36x=0
We add all the numbers together, and all the variables
100x^2+12x=0
a = 100; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·100·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*100}=\frac{-24}{200} =-3/25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*100}=\frac{0}{200} =0 $
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