2(3r+4)=3(r+1)=11

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Solution for 2(3r+4)=3(r+1)=11 equation: 



2(3r+4)=3(r+1)=11

We move all terms to the left:

2(3r+4)-(3(r+1))=0

We multiply parentheses

6r-(3(r+1))+8=0



We calculate terms in parentheses: -(3(r+1)), so:

3(r+1)

We multiply parentheses

3r+3

Back to the equation:

-(3r+3)



We get rid of parentheses

6r-3r-3+8=0

We add all the numbers together, and all the variables

3r+5=0

We move all terms containing r to the left, all other terms to the right

3r=-5

r=-5/3

r=-1+2/3

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