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2/x+1=3x/5x-1
We move all terms to the left:
2/x+1-(3x/5x-1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x-1)!=0We get rid of parentheses
x∈R
2/x-3x/5x+1+1=0
We calculate fractions
(-3x^2)/5x^2+10x/5x^2+1+1=0
We add all the numbers together, and all the variables
(-3x^2)/5x^2+10x/5x^2+2=0
We multiply all the terms by the denominator
(-3x^2)+10x+2*5x^2=0
Wy multiply elements
(-3x^2)+10x^2+10x=0
We get rid of parentheses
-3x^2+10x^2+10x=0
We add all the numbers together, and all the variables
7x^2+10x=0
a = 7; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·7·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*7}=\frac{-20}{14} =-1+3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*7}=\frac{0}{14} =0 $
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