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2/g+6=4/5g+10
We move all terms to the left:
2/g+6-(4/5g+10)=0
Domain of the equation: g!=0
g∈R
Domain of the equation: 5g+10)!=0We get rid of parentheses
g∈R
2/g-4/5g-10+6=0
We calculate fractions
10g/5g^2+(-4g)/5g^2-10+6=0
We add all the numbers together, and all the variables
10g/5g^2+(-4g)/5g^2-4=0
We multiply all the terms by the denominator
10g+(-4g)-4*5g^2=0
Wy multiply elements
-20g^2+10g+(-4g)=0
We get rid of parentheses
-20g^2+10g-4g=0
We add all the numbers together, and all the variables
-20g^2+6g=0
a = -20; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-20)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-20}=\frac{-12}{-40} =3/10 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-20}=\frac{0}{-40} =0 $
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