3(4x-5)=9x+12

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Solution for 3(4x-5)=9x+12 equation: 



3(4x-5)=9x+12

We move all terms to the left:

3(4x-5)-(9x+12)=0

We multiply parentheses

12x-(9x+12)-15=0

We get rid of parentheses

12x-9x-12-15=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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