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2/9p+3=1/4p
We move all terms to the left:
2/9p+3-(1/4p)=0
Domain of the equation: 9p!=0
p!=0/9
p!=0
p∈R
Domain of the equation: 4p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
2/9p-(+1/4p)+3=0
We get rid of parentheses
2/9p-1/4p+3=0
We calculate fractions
8p/36p^2+(-9p)/36p^2+3=0
We multiply all the terms by the denominator
8p+(-9p)+3*36p^2=0
Wy multiply elements
108p^2+8p+(-9p)=0
We get rid of parentheses
108p^2+8p-9p=0
We add all the numbers together, and all the variables
108p^2-1p=0
a = 108; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·108·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*108}=\frac{0}{216} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*108}=\frac{2}{216} =1/108 $
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