2/3(n+1)=1/6(3n-5)

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Solution for 2/3(n+1)=1/6(3n-5) equation: 



2/3(n+1)=1/6(3n-5)

We move all terms to the left:

2/3(n+1)-(1/6(3n-5))=0



Domain of the equation: 3(n+1)!=0

n∈R





Domain of the equation: 6(3n-5))!=0

n∈R



We calculate fractions


(12n3/(3(n+1)*6(3n-5)))+(-3nn/(3(n+1)*6(3n-5)))=0



We calculate terms in parentheses: +(12n3/(3(n+1)*6(3n-5))), so:

12n3/(3(n+1)*6(3n-5))

We multiply all the terms by the denominator


12n3

We add all the numbers together, and all the variables

12n^3

We do not support enpression: n^3

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