2/7x=10x=35

Solution for 2/7x=10x=35 equation:

2/7x=10x=35

We move all terms to the left:

2/7x-(10x)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R


We add all the numbers together, and all the variables

-10x+2/7x=0

We multiply all the terms by the denominator


-10x*7x+2=0

Wy multiply elements

-70x^2+2=0

a = -70; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-70)·2
Δ = 560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{560}=\sqrt{16*35}=\sqrt{16}*\sqrt{35}=4\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{35}}{2*-70}=\frac{0-4\sqrt{35}}{-140}
=-\frac{4\sqrt{35}}{-140}
=-\frac{\sqrt{35}}{-35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{35}}{2*-70}=\frac{0+4\sqrt{35}}{-140}
=\frac{4\sqrt{35}}{-140}
=\frac{\sqrt{35}}{-35}
$