(2e+10)(-e+15)=0

Solution for (2e+10)(-e+15)=0 equation:

(2e+10)(-e+15)=0

We add all the numbers together, and all the variables

(2e+10)(-1e+15)=0

We multiply parentheses ..

(-2e^2+30e-10e+150)=0

We get rid of parentheses

-2e^2+30e-10e+150=0

We add all the numbers together, and all the variables

-2e^2+20e+150=0

a = -2; b = 20; c = +150;
Δ = b2-4ac
Δ = 202-4·(-2)·150
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*-2}=\frac{-60}{-4}
=+15
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*-2}=\frac{20}{-4}
=-5
$