2/6y+4=3/12y-6

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Solution for 2/6y+4=3/12y-6 equation:



2/6y+4=3/12y-6
We move all terms to the left:
2/6y+4-(3/12y-6)=0
Domain of the equation: 6y!=0
y!=0/6
y!=0
y∈R
Domain of the equation: 12y-6)!=0
y∈R
We get rid of parentheses
2/6y-3/12y+6+4=0
We calculate fractions
24y/72y^2+(-18y)/72y^2+6+4=0
We add all the numbers together, and all the variables
24y/72y^2+(-18y)/72y^2+10=0
We multiply all the terms by the denominator
24y+(-18y)+10*72y^2=0
Wy multiply elements
720y^2+24y+(-18y)=0
We get rid of parentheses
720y^2+24y-18y=0
We add all the numbers together, and all the variables
720y^2+6y=0
a = 720; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·720·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*720}=\frac{-12}{1440} =-1/120 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*720}=\frac{0}{1440} =0 $

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