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(x+9)(x-2)-(x-5)(x+5)=-14
We move all terms to the left:
(x+9)(x-2)-(x-5)(x+5)-(-14)=0
We add all the numbers together, and all the variables
(x+9)(x-2)-(x-5)(x+5)+14=0
We use the square of the difference formula
x^2+(x+9)(x-2)+25+14=0
We multiply parentheses ..
x^2+(+x^2-2x+9x-18)+25+14=0
We add all the numbers together, and all the variables
x^2+(+x^2-2x+9x-18)+39=0
We get rid of parentheses
x^2+x^2-2x+9x-18+39=0
We add all the numbers together, and all the variables
2x^2+7x+21=0
a = 2; b = 7; c = +21;
Δ = b2-4ac
Δ = 72-4·2·21
Δ = -119
Delta is less than zero, so there is no solution for the equation
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