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2/6x-5=2x+6
We move all terms to the left:
2/6x-5-(2x+6)=0
Domain of the equation: 6x!=0We get rid of parentheses
x!=0/6
x!=0
x∈R
2/6x-2x-6-5=0
We multiply all the terms by the denominator
-2x*6x-6*6x-5*6x+2=0
Wy multiply elements
-12x^2-36x-30x+2=0
We add all the numbers together, and all the variables
-12x^2-66x+2=0
a = -12; b = -66; c = +2;
Δ = b2-4ac
Δ = -662-4·(-12)·2
Δ = 4452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4452}=\sqrt{4*1113}=\sqrt{4}*\sqrt{1113}=2\sqrt{1113}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-2\sqrt{1113}}{2*-12}=\frac{66-2\sqrt{1113}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+2\sqrt{1113}}{2*-12}=\frac{66+2\sqrt{1113}}{-24} $
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