7-(y+3(y+2))=0

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Solution for 7-(y+3(y+2))=0 equation: 



7-(y+3(y+2))=0



We calculate terms in parentheses: -(y+3(y+2)), so:

y+3(y+2)

We multiply parentheses

y+3y+6

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)



We get rid of parentheses

-4y-6+7=0

We add all the numbers together, and all the variables

-4y+1=0

We move all terms containing y to the left, all other terms to the right

-4y=-1

y=-1/-4

y=1/4

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