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2/5x-3=6-1/2x
We move all terms to the left:
2/5x-3-(6-1/2x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/5x-(-1/2x+6)-3=0
We get rid of parentheses
2/5x+1/2x-6-3=0
We calculate fractions
4x/10x^2+5x/10x^2-6-3=0
We add all the numbers together, and all the variables
4x/10x^2+5x/10x^2-9=0
We multiply all the terms by the denominator
4x+5x-9*10x^2=0
We add all the numbers together, and all the variables
9x-9*10x^2=0
Wy multiply elements
-90x^2+9x=0
a = -90; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-90)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-90}=\frac{-18}{-180} =1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-90}=\frac{0}{-180} =0 $
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