3(x-2)/2=3(x+1)/5

Solution for 3(x-2)/2=3(x+1)/5 equation:

3(x-2)/2=3(x+1)/5

We move all terms to the left:

3(x-2)/2-(3(x+1)/5)=0

We calculate fractions


3x/()+(-(3(x+1)*2)/()=0


We calculate terms in parentheses: +(-(3(x+1)*2)/(), so:

-(3(x+1)*2)/(

We multiply all the terms by the denominator


-(3(x+1)*2)


We calculate terms in parentheses: -(3(x+1)*2), so:

3(x+1)*2

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)


We get rid of parentheses

-6x-6

Back to the equation:

+(-6x-6)


We get rid of parentheses

3x/()-6x-6=0

We multiply all the terms by the denominator


3x-6x*()-6*()=0

We add all the numbers together, and all the variables

3x-6x*()=0