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2/5x-12=13
We move all terms to the left:
2/5x-12-(13)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/5x-25=0
We multiply all the terms by the denominator
-25*5x+2=0
Wy multiply elements
-125x+2=0
We move all terms containing x to the left, all other terms to the right
-125x=-2
x=-2/-125
x=2/125
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