2/5x-10=1/2x-45

Solution for 2/5x-10=1/2x-45 equation:

2/5x-10=1/2x-45

We move all terms to the left:

2/5x-10-(1/2x-45)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 2x-45)!=0

x∈R


We get rid of parentheses

2/5x-1/2x+45-10=0

We calculate fractions


4x/10x^2+(-5x)/10x^2+45-10=0

We add all the numbers together, and all the variables

4x/10x^2+(-5x)/10x^2+35=0

We multiply all the terms by the denominator


4x+(-5x)+35*10x^2=0

Wy multiply elements

350x^2+4x+(-5x)=0

We get rid of parentheses

350x^2+4x-5x=0

We add all the numbers together, and all the variables

350x^2-1x=0

a = 350; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·350·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*350}=\frac{0}{700}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*350}=\frac{2}{700}
=1/350
$