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2/5x+9=8x
We move all terms to the left:
2/5x+9-(8x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-8x+2/5x+9=0
We multiply all the terms by the denominator
-8x*5x+9*5x+2=0
Wy multiply elements
-40x^2+45x+2=0
a = -40; b = 45; c = +2;
Δ = b2-4ac
Δ = 452-4·(-40)·2
Δ = 2345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2345}}{2*-40}=\frac{-45-\sqrt{2345}}{-80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2345}}{2*-40}=\frac{-45+\sqrt{2345}}{-80} $
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