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2/5x+5=1/3x+14
We move all terms to the left:
2/5x+5-(1/3x+14)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x+14)!=0We get rid of parentheses
x∈R
2/5x-1/3x-14+5=0
We calculate fractions
6x/15x^2+(-5x)/15x^2-14+5=0
We add all the numbers together, and all the variables
6x/15x^2+(-5x)/15x^2-9=0
We multiply all the terms by the denominator
6x+(-5x)-9*15x^2=0
Wy multiply elements
-135x^2+6x+(-5x)=0
We get rid of parentheses
-135x^2+6x-5x=0
We add all the numbers together, and all the variables
-135x^2+x=0
a = -135; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-135)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-135}=\frac{-2}{-270} =1/135 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-135}=\frac{0}{-270} =0 $
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