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(2x+5)+(3-10)=70
We move all terms to the left:
(2x+5)+(3-10)-(70)=0
determiningTheFunctionDomain (2x+5)-70+(3-10)=0
We add all the numbers together, and all the variables
(2x+5)-70+(-7)=0
We add all the numbers together, and all the variables
(2x+5)-77=0
We get rid of parentheses
2x+5-77=0
We add all the numbers together, and all the variables
2x-72=0
We move all terms containing x to the left, all other terms to the right
2x=72
x=72/2
x=36
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