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2/5x+15=x-
We move all terms to the left:
2/5x+15-(x-)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/5x-(+x)+15=0
We get rid of parentheses
2/5x-x+15=0
We multiply all the terms by the denominator
-x*5x+15*5x+2=0
Wy multiply elements
-5x^2+75x+2=0
a = -5; b = 75; c = +2;
Δ = b2-4ac
Δ = 752-4·(-5)·2
Δ = 5665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{5665}}{2*-5}=\frac{-75-\sqrt{5665}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{5665}}{2*-5}=\frac{-75+\sqrt{5665}}{-10} $
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