2/5p-2/7p+2=6

Solution for 2/5p-2/7p+2=6 equation:

2/5p-2/7p+2=6

We move all terms to the left:

2/5p-2/7p+2-(6)=0


Domain of the equation: 5p!=0

p!=0/5

p!=0

p∈R



Domain of the equation: 7p!=0

p!=0/7

p!=0

p∈R


We add all the numbers together, and all the variables

2/5p-2/7p-4=0

We calculate fractions


14p/35p^2+(-10p)/35p^2-4=0

We multiply all the terms by the denominator


14p+(-10p)-4*35p^2=0

Wy multiply elements

-140p^2+14p+(-10p)=0

We get rid of parentheses

-140p^2+14p-10p=0

We add all the numbers together, and all the variables

-140p^2+4p=0

a = -140; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-140)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-140}=\frac{-8}{-280}
=1/35
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-140}=\frac{0}{-280}
=0
$