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(5x+24)/(9x-17)=x
We move all terms to the left:
(5x+24)/(9x-17)-(x)=0
Domain of the equation: (9x-17)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
9x!=17
x!=17/9
x!=1+8/9
x∈R
-1x+(5x+24)/(9x-17)=0
We multiply all the terms by the denominator
-1x*(9x-17)+(5x+24)=0
We multiply parentheses
-9x^2+17x+(5x+24)=0
We get rid of parentheses
-9x^2+17x+5x+24=0
We add all the numbers together, and all the variables
-9x^2+22x+24=0
a = -9; b = 22; c = +24;
Δ = b2-4ac
Δ = 222-4·(-9)·24
Δ = 1348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1348}=\sqrt{4*337}=\sqrt{4}*\sqrt{337}=2\sqrt{337}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{337}}{2*-9}=\frac{-22-2\sqrt{337}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{337}}{2*-9}=\frac{-22+2\sqrt{337}}{-18} $
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