2/5h-7=12/5h-2+3

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Solution for 2/5h-7=12/5h-2+3 equation: 



2/5h-7=12/5h-2+3

We move all terms to the left:

2/5h-7-(12/5h-2+3)=0



Domain of the equation: 5h!=0

h!=0/5

h!=0

h∈R





Domain of the equation: 5h-2+3)!=0

We move all terms containing h to the left, all other terms to the right

5h+3)!=2

h∈R



We add all the numbers together, and all the variables

2/5h-(12/5h+1)-7=0

We get rid of parentheses

2/5h-12/5h-1-7=0

We multiply all the terms by the denominator


-1*5h-7*5h+2-12=0

We add all the numbers together, and all the variables

-1*5h-7*5h-10=0

Wy multiply elements

-5h-35h-10=0

We add all the numbers together, and all the variables

-40h-10=0

We move all terms containing h to the left, all other terms to the right

-40h=10

h=10/-40

h=-1/4

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