(5/2)y+(1/4)=(3/4)y+2

Solution for (5/2)y+(1/4)=(3/4)y+2 equation:

(5/2)y+(1/4)=(3/4)y+2

We move all terms to the left:

(5/2)y+(1/4)-((3/4)y+2)=0


Domain of the equation: 2)y!=0

y!=0/1

y!=0

y∈R



Domain of the equation: 4)y+2)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+5/2)y-((+3/4)y+2)+(+1/4)=0

We multiply parentheses

5y^2-((+3/4)y+2)+(+1/4)=0

We get rid of parentheses

5y^2-((+3/4)y+2)+1/4=0

We calculate fractions


5y^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{10}=0$