2/5c=+4-1/2c=-9

Solution for 2/5c=+4-1/2c=-9 equation:

2/5c=+4-1/2c=-9

We move all terms to the left:

2/5c-(+4-1/2c)=0


Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



Domain of the equation: 2c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

2/5c-(-1/2c+4)=0

We get rid of parentheses

2/5c+1/2c-4=0

We calculate fractions


4c/10c^2+5c/10c^2-4=0

We multiply all the terms by the denominator


4c+5c-4*10c^2=0

We add all the numbers together, and all the variables

9c-4*10c^2=0

Wy multiply elements

-40c^2+9c=0

a = -40; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-40)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-40}=\frac{-18}{-80}
=9/40
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-40}=\frac{0}{-80}
=0
$