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-4.905x^2-5x+92.2=0
a = -4.905; b = -5; c = +92.2;
Δ = b2-4ac
Δ = -52-4·(-4.905)·92.2
Δ = 1833.964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1833.964}}{2*-4.905}=\frac{5-\sqrt{1833.964}}{-9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1833.964}}{2*-4.905}=\frac{5+\sqrt{1833.964}}{-9.81} $
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