2/5c+4/5c-6=7

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Solution for 2/5c+4/5c-6=7 equation: 



2/5c+4/5c-6=7

We move all terms to the left:

2/5c+4/5c-6-(7)=0



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



We add all the numbers together, and all the variables

2/5c+4/5c-13=0

We multiply all the terms by the denominator


-13*5c+2+4=0

We add all the numbers together, and all the variables

-13*5c+6=0

Wy multiply elements

-65c+6=0

We move all terms containing c to the left, all other terms to the right

-65c=-6

c=-6/-65

c=6/65

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