(2u-20)+(u-6)+(3u-16)=180

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Solution for (2u-20)+(u-6)+(3u-16)=180 equation: 



(2u-20)+(u-6)+(3u-16)=180

We move all terms to the left:

(2u-20)+(u-6)+(3u-16)-(180)=0

We get rid of parentheses

2u+u+3u-20-6-16-180=0

We add all the numbers together, and all the variables

6u-222=0

We move all terms containing u to the left, all other terms to the right

6u=222

u=222/6

u=37

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