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2/5+4/x=1/10x
We move all terms to the left:
2/5+4/x-(1/10x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4/x-(+1/10x)+2/5=0
We get rid of parentheses
4/x-1/10x+2/5=0
We calculate fractions
20x^2/250x^2+1000x/250x^2+(-25x)/250x^2=0
We multiply all the terms by the denominator
20x^2+1000x+(-25x)=0
We get rid of parentheses
20x^2+1000x-25x=0
We add all the numbers together, and all the variables
20x^2+975x=0
a = 20; b = 975; c = 0;
Δ = b2-4ac
Δ = 9752-4·20·0
Δ = 950625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{950625}=975$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(975)-975}{2*20}=\frac{-1950}{40} =-48+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(975)+975}{2*20}=\frac{0}{40} =0 $
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